(y-4)(4y^2-3y+5)=

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Solution for (y-4)(4y^2-3y+5)= equation: 


Simplifying
(y + -4)(4y2 + -3y + 5) = 0

Reorder the terms:
(-4 + y)(4y2 + -3y + 5) = 0

Reorder the terms:
(-4 + y)(5 + -3y + 4y2) = 0

Multiply (-4 + y) * (5 + -3y + 4y2)
(-4(5 + -3y + 4y2) + y(5 + -3y + 4y2)) = 0
((5 * -4 + -3y * -4 + 4y2 * -4) + y(5 + -3y + 4y2)) = 0
((-20 + 12y + -16y2) + y(5 + -3y + 4y2)) = 0
(-20 + 12y + -16y2 + (5 * y + -3y * y + 4y2 * y)) = 0
(-20 + 12y + -16y2 + (5y + -3y2 + 4y3)) = 0

Reorder the terms:
(-20 + 12y + 5y + -16y2 + -3y2 + 4y3) = 0

Combine like terms: 12y + 5y = 17y
(-20 + 17y + -16y2 + -3y2 + 4y3) = 0

Combine like terms: -16y2 + -3y2 = -19y2
(-20 + 17y + -19y2 + 4y3) = 0

Solving
-20 + 17y + -19y2 + 4y3 = 0

Solving for variable 'y'.

The solution to this equation could not be determined.

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